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Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct.
Example 1:
Input: nums = [1,2,3,1] Output: true
Example 2:
Input: nums = [1,2,3,4] Output: false
Example 3:
Input: nums = [1,1,1,3,3,4,3,2,4,2] Output: true
Constraints:
1 <= nums.length <= 10 5-10 9 <= nums[i] <= 10 9
Python
class Solution: def containsDuplicate(self, nums: List[int]) -> bool: nums.sort() for i in range(len(nums)-1): if nums[i] == nums[i+1] : return True return False
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