[LeetCode] 0016. 3Sum Closest

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内容目录

Medium

Given an integer array nums of length n and an integer target, find three integers in nums such that the sum is closest to target.

Return the sum of the three integers.

You may assume that each input would have exactly one solution.

Example 1:

Input: nums = [-1,2,1,-4], target = 1
Output: 2
Explanation: The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

Example 2:

Input: nums = [0,0,0], target = 1
Output: 0
Explanation: The sum that is closest to the target is 0. (0 + 0 + 0 = 0).

Constraints:

3 <= nums.length <= 500
-1000 <= nums[i] <= 1000
-10 ⁴ <= target <= 10 ⁴

Python

				
					# time complexity: O(n) # space complexity: O(n) from typing import List class Solution(object): def maxProfit(self, prices: List[int]) -> int: if len(prices) <= 1 : return 0 leftMin = prices[0] rightMax = prices[-1] length = len(prices) leftProfits = [0] * length rightProfits = [0] * (length + 1) for l in range(1, length): leftProfits[l] = max(leftProfits[l - 1], prices[l] - leftMin) leftMin = min(leftMin, prices[l]) r = length - 1 - l rightProfits[r] = max(rightProfits[r + 1], rightMax - prices[r]) rightMax = max(rightMax, prices[r]) maxProfit = 0 print(leftProfits) print(rightProfits) for i in range(0, length): maxProfit = max(maxProfit, leftProfits[ i] + rightProfits[i + 1]) return maxProfit prices = [7, 1, 5, 3, 6, 4] # leftProfit = [0, 0, 4, 4, 5, 5] # rightProfit = [5, 5 , 3, 3, 0, 0, 0] print(Solution().maxProfit(prices))

Medium

Python

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