Explore diverse LeetCode solutions in Python, C++, JavaScript, SQL, and TypeScript. Ideal for interview prep, learning, and code practice in multiple programming languages. Github Repo Link
A trie (pronounced as “try”) or prefix tree is a tree data structure used to efficiently store and retrieve keys in a dataset of strings. There are various applications of this data structure, such as autocomplete and spellchecker.
Implement the Trie class:
Trie()
Initializes the trie object.void insert(String word)
Inserts the stringword
into the trie.int countWordsEqualTo(String word)
Returns the number of instances of the stringword
in the trie.int countWordsStartingWith(String prefix)
Returns the number of strings in the trie that have the stringprefix
as a prefix.void erase(String word)
Erases the stringword
from the trie.
Example 1:
Input ["Trie", "insert", "insert", "countWordsEqualTo", "countWordsStartingWith", "erase", "countWordsEqualTo", "countWordsStartingWith", "erase", "countWordsStartingWith"] [[], ["apple"], ["apple"], ["apple"], ["app"], ["apple"], ["apple"], ["app"], ["apple"], ["app"]] Output [null, null, null, 2, 2, null, 1, 1, null, 0] Explanation Trie trie = new Trie(); trie.insert("apple"); // Inserts "apple". trie.insert("apple"); // Inserts another "apple". trie.countWordsEqualTo("apple"); // There are two instances of "apple" so return 2. trie.countWordsStartingWith("app"); // "app" is a prefix of "apple" so return 2. trie.erase("apple"); // Erases one "apple". trie.countWordsEqualTo("apple"); // Now there is only one instance of "apple" so return 1. trie.countWordsStartingWith("app"); // return 1 trie.erase("apple"); // Erases "apple". Now the trie is empty. trie.countWordsStartingWith("app"); // return 0
Constraints:
1 <= word.length, prefix.length <= 2000
word
andprefix
consist only of lowercase English letters.- At most
3 * 10 4
calls in total will be made toinsert
,countWordsEqualTo
,countWordsStartingWith
, anderase
. - It is guaranteed that for any function call to
erase
, the stringword
will exist in the trie.
Python
class TrieNode: def __init__(self): self.links = [None] * 26 self.wordsEndingHere = 0 self.wordsStartingHere = 0 class Trie: def __init__(self): self.root = TrieNode() def insert(self, word: str) -> None: node = self.root for w in word: charIndex = ord(w) - ord('a') if not node.links[charIndex]: node.links[charIndex] = TrieNode() node = node.links[charIndex] node.wordsStartingHere += 1 node.wordsEndingHere += 1 def countWordsEqualTo(self, word: str) -> int: node = self.root for w in word: charIndex = ord(w) - ord('a') if not node.links[charIndex]: return 0 node = node.links[charIndex] return node.wordsEndingHere def countWordsStartingWith(self, prefix: str) -> int: node = self.root for w in prefix: charIndex = ord(w) - ord('a') if not node.links[charIndex]: return 0 node = node.links[charIndex] return node.wordsStartingHere def erase(self, word: str) -> None: node = self.root for w in word: charIndex = ord(w) - ord('a') node = node.links[charIndex] node.wordsStartingHere -= 1 node.wordsEndingHere -= 1 # Your Trie object will be instantiated and called as such: trie = Trie() trie.insert("apple") trie.insert("apple") print(trie.countWordsEqualTo("apple")) print(trie.countWordsStartingWith("app")) trie.erase("apple") print(trie.countWordsEqualTo("apple")) print(trie.countWordsStartingWith("app")) trie.erase("apple") print(trie.countWordsStartingWith("app"))