[LeetCode] 0219. Contains Duplicate II

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内容目录

Easy

 


Given an integer array nums and an integer k, return true if there are two distinct indices i and j in the array such that nums[i] == nums[j] and abs(i - j) <= k.

Example 1:

Input: nums = [1,2,3,1], k = 3
Output: true

Example 2:

Input: nums = [1,0,1,1], k = 1
Output: true

Example 3:

Input: nums = [1,2,3,1,2,3], k = 2
Output: false

Constraints:

  • 1 <= nums.length <= 10 5
  • -10 9 <= nums[i] <= 10 9
  • 0 <= k <= 10 5

Python

				
					# time complexity: O(n) # space complexity: O(min(n,k)) from typing import List class Solution: def containsNearbyDuplicate(self, nums: List[int], k: int) -> bool: dic = {} for i, j in enumerate(nums): if j in dic and i - dic[j] <= k: return True dic[j] = i return False nums = [1, 2, 3, 1] k = 3 print(Solution().containsNearbyDuplicate(nums, k))
				
			
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