[LeetCode] 1143. Longest Common Subsequence

Longest Common Subsequence

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内容目录

Medium


Given two strings text1 and text2, return the length of their longest common subsequenceIf there is no common subsequence, return 0.

subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.

  • For example, "ace" is a subsequence of "abcde".

common subsequence of two strings is a subsequence that is common to both strings.

 

Example 1:

Input: text1 = "abcde", text2 = "ace" 
Output: 3  
Explanation: The longest common subsequence is "ace" and its length is 3.

Example 2:

Input: text1 = "abc", text2 = "abc"
Output: 3
Explanation: The longest common subsequence is "abc" and its length is 3.

Example 3:

Input: text1 = "abc", text2 = "def"
Output: 0
Explanation: There is no such common subsequence, so the result is 0.

 

Constraints:

  • 1 <= text1.length, text2.length <= 1000
  • text1 and text2 consist of only lowercase English characters.

Python

				
					# time complexity: O(n*m) # space compleixty: O(n*m) class Solution: def longestCommonSubsequence(self, text1: str, text2: str) -> int: dpGrid = [[0] * (len( text2) + 1) for _ in range(len(text1)+1)] for col in reversed(range(len(text2))): for row in reversed(range(len(text1))): if text2[col ] == text1[row]: dpGrid[row][col] = 1 + dpGrid[row+1][col+1] else: dpGrid[row][col] = max( dpGrid[row+1][col] , dpGrid[row][col+1]) return dpGrid[0][0] text1 = "abcde" text2 = "ace" print(Solution().longestCommonSubsequence(text1, text2))
				
			
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