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Given an m x n
integer matrix matrix
, if an element is 0
, set its entire row and column to 0
‘s.
You must do it in place.
Example 1:
Input: matrix = [[1,1,1],[1,0,1],[1,1,1]] Output: [[1,0,1],[0,0,0],[1,0,1]]
Example 2:
Input: matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]] Output: [[0,0,0,0],[0,4,5,0],[0,3,1,0]]
Constraints:
m == matrix.length
n == matrix[0].length
1 <= m, n <= 200
-231 <= matrix[i][j] <= 231 - 1
Follow up:
- A straightforward solution using
O(mn)
space is probably a bad idea. - A simple improvement uses
O(m + n)
space, but still not the best solution. - Could you devise a constant space solution?
內容目錄
TogglePython
# time complexity: O(m*n)
# space complexity: O(m+n)
from typing import List
class Solution:
def setZeroes(self, matrix: List[List[int]]) -> None:
rowSet, colSet = set(), set()
for r in range(len(matrix)):
for c in range(len(matrix[0])):
if matrix[r][c] == 0:
rowSet.add(r)
colSet.add(c)
for r in range(len(matrix)):
for c in range(len(matrix[0])):
if r in rowSet or c in colSet:
matrix[r][c] = 0
matrix = [[0, 1, 2, 0], [3, 4, 5, 2], [1, 3, 1, 5]]
print(Solution().setZeroes(matrix))