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內容目錄
ToggleEasy
Given an integer array nums
, return true
if any value appears at least twice in the array, and return false
if every element is distinct.
Example 1:
Input: nums = [1,2,3,1] Output: true
Example 2:
Input: nums = [1,2,3,4] Output: false
Example 3:
Input: nums = [1,1,1,3,3,4,3,2,4,2] Output: true
Constraints:
1 <= nums.length <= 105
-109 <= nums[i] <= 109
Python
class Solution:
def containsDuplicate(self, nums: List[int]) -> bool:
nums.sort()
for i in range(len(nums)-1):
if nums[i] == nums[i+1]:
return True
return False