[LeetCode] 0219. Contains Duplicate II

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內容目錄

Easy

 


Given an integer array nums and an integer k, return true if there are two distinct indices i and j in the array such that nums[i] == nums[j] and abs(i - j) <= k.

Example 1:

Input: nums = [1,2,3,1], k = 3
Output: true

Example 2:

Input: nums = [1,0,1,1], k = 1
Output: true

Example 3:

Input: nums = [1,2,3,1,2,3], k = 2
Output: false

Constraints:

  • 1 <= nums.length <= 105
  • -109 <= nums[i] <= 109
  • 0 <= k <= 105

Python

				
					# time complexity: O(n)
# space complexity: O(min(n,k))
from typing import List


class Solution:
    def containsNearbyDuplicate(self, nums: List[int], k: int) -&gt; bool:
        dic = {}
        for i, j in enumerate(nums):
            if j in dic and i - dic[j] &lt;= k:
                return True
            dic[j] = i
        return False


nums = [1, 2, 3, 1]
k = 3
print(Solution().containsNearbyDuplicate(nums, k))
				
			
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